The pressure exerted by `12 g` of an ideal gas at temperature `t^(@)C` in a vessel of volume `V litre` is `1 atm`. When the temperature is increased by `10^(@)C` at the same volume, the pressure increases by `10%`. Calculate the temperature `t` and volume `V`. (Molecular weight of the gas is `120`).

Answer

`-173^(@), 0.82L`

Explanation

For a fixed amount and volume, `p prop T`
`rArr (1)/(1.1) = (T)/(T + 10)` where, Kelvin temperature `rArr T = 100K = t + 273 rArr t = -173^(@)C`
Volume `=(nRT)/(p) = ((12)/(120)) xx (0.082 xx 100)/(1) = 0.82L`