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When 4.215 g of a metallic carbonate was...

When `4.215 g` of a metallic carbonate was heated in a hard glass tube, the `CO_(2)` evolved was found to measure `1336 mL` at `27^(@)C` and `700 mm` pressure. What is the equivalent weight of the metal?

Text Solution

Verified by Experts

The correct Answer is:
(12. 15)
Moles of `CO_(2)` can be calculated using ideal gas equation as :
`n = (pV)/(RT) = ((700)/(760)) ((1336)/(1000)) xx (1)/(0.082 xx 300) = 0.05`
Also, the decomposition reaction is: `underset(0.05 mol)(MCO_(3)) rarr underset(0.05 mol) (MO + CO_(2))`
`:'` 0.05 mole `MCO_(3) = 4.215g :.` 1.0 mole `M CO_(3) = (4.215)/(0.05) = 84.3` g(molar mass)
`rArr 84.3 = MW " of" M + 12 + 48 rArr` Molecular weight of metal = 24.3
`:.` Metal is bivalent, equivalent weight `= ("Molecular weight")/(2) = 12.15`
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