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According to Graham's law, at a given te...

According to Graham's law, at a given temperature, the ratio of the rates of diffusion `r_(A)//r_(B)` of gases `A` and `B` is given by

A

`((p_(A))/(p_(B))) ((M_(A))/(M_(B)))^((1)/(2))`

B

`((M_(A))/(M_(B))) ((p_(A))/(p_(B)))^((1)/(2))`

C

`((p_(A))/(p_(B))) ((M_(B))/(M_(A)))^((1)/(2))`

D

`((M_(A))/(M_(B))) ((p_(B))/(p_(A)))^((1)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`(p_(A))/(p_(B)) = (n_(A))/(n_(B)) sqrt((M_(B))/(M_(A)))` (at constant T and V)
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