The enthalpy of evaporation of water at 373 K is `40.67 kJ mol^(-1)`. What will be the enthalpy of evaporation at 353 K and 393 K if average molar heats at constant pressure in this range for water in liquid and vapour states are 75.312 and `33.89 JK^(-1) mol^(-1)` respectively?

Explanation

To find the enthalpy of evaporation of water at 353 K and 393 K, we can use the following formula derived from the concept of heat capacities:

\[ \Delta H_2 = \Delta H_1 + \Delta C_p (T_2 - T_1) \]

Where:
- \(\Delta H_1\) is the enthalpy of evaporation at the reference temperature (373 K).
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