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Whenever an acid is neutralized by a bas...

Whenever an acid is neutralized by a base, the net reaction is
`H^(o+) (aq) + bar(O)H(aq) to H_(2)O(l) (l) , Delta H = -57.1 kJ`.
Calculate the heat evolved for the following experiment?
0.50 mol of solution is mixed with 0.30 mol of KOH solution.

Text Solution

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According to the reaction `H^(+) (aq) + OH^(+) (aq) to H_(2)O (l) , DeltaH = -57.1 kJ`
When 1 mol of ions and 1 mol of ions are neutralized, 1 mol of water is formed and 57.1 kJ of energy is released.
`0.50 mol HNO_(3) = 0.50 mol H^(+)`ions i.e. 0.30 mol of `H^+` ions reacts with 0.30 mol of `OH^(-)`
ions to form 0.30 mol of water molecules
Heat evolved in the formation of 0.3 mol of water `= 57.1 xx 0.3 = 17.13 kJ`.
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