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C(s)+O(2)(g)toCO(2)(g),DeltaH=-94 kcal ...

`C(s)+O_(2)(g)toCO_(2)(g),DeltaH=-94` kcal
`2CO(g)+O_(2)to2CO_(2),DeltaH=-135.2` kcal
The heat of formation of `CO(g)` is

A

`-26.4` kcal

B

`41.2 kcal`

C

`26.4 kcal`

D

`229.2 kcal`

Text Solution

Verified by Experts

The correct Answer is:
A
The heat of formation of CO is calculated by using Hess’s law. According to it, the total heat change occurring during a chemical reaction is independent of path.
`2CO(g) + O_(2)(g) to 2CO_(2)(g) ," " DeltaH = (135.2)kcal`
I. `CO_2(g) to CO(g) + 1/2 O_2 (g) ," " Delta H = (135.2)/(2) kcal`
II. `C(s) + O_(2)(g) to CO_(2)(g) , " "Delta H = -94 kcal`
Required equation: `C(s) + 1/2O_(2)(g) to CO(g) , " "DeltaH = ?`
Add eqs. (I) and (ii) `" "C(s) + 1/2 O_(2)(g) to CO(g), " "DeltaH = -26.4 kcal`.
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