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The amount of heat released when 20 ml,0...

The amount of heat released when `20 ml`,`0.5 M` `NaOH`is mixed with `100 ml`,`0.1 M` `H_(2)SO_(4)` is `xKJ`. The heat of neutralization will be `:-`

A

`-100 x kJ//mol`

B

`-50 x kJ//mol`

C

`+100 x kJ//mol`

D

`+50 x kJ//mol`

Text Solution

Verified by Experts

The correct Answer is:
A
`NaOH + HCl to NaCl + H_(2)O`
`20 mL " "100 mL`
`0.5 M" "0.1 M`
10 m moles `" "`10 m moles
0.01 moles `" "` 0.01 moles
Applying unitary method
0.01 mole of acid and base release `=x kJ`
1 mole of acid and base release `= x/(0.01) kJ//mol = -100x kJ//mol`
-ve sign shows energy is released.
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