The value of enthalpy change `(DeltaH)` for the reaction
`C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(l)`
at `27^(@)C` is `-1366.5KJmol^(-1)` . The value of internal energy change for the above reaction at this tempearature will be

Options

A. `-1371.5 kJ`
B. `-1369.0 kJ`
C. `-1364.0 kJ`
D. `1361.5 kJ`

Answer

C

Explanation

Relation between `DeltaH` enthalpy change) and `DeltaE` (internal energy change) is `: Delta H = Delta E + Delta_(n_g) RT`
Where, `Delta_(n_g)` = moles of gaseous products -moles of gaseous reactants = 2 - 3 = -1
`implies -1366.5 = DeltaE - 1 xx 8.314 xx 10^(-3) xx 300`
`Delta E = -1364.0 kJ mol^(-1)`.