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The H-H bond energy is 430KJmol^(-1) and...

The `H-H` bond energy is `430KJmol^(-1)` and `Cl-Cl` bond energy is `240KJmol^(-1)` . `DeltaH` for `HCl` is `-90KJ` . The `H-Cl` bond energy is about

A

`180 kJ mol^(-1)`

B

`360 kJ mol^(-1)`

C

`213 kJ mol^(-1)`

D

`425 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
The formation of one mole of HCl can be represented as
`1/2 (H - H) + 1/2 (Cl - Cl) to H - Cl , Delta H = -90 kJ`
Hence, for the reaction.
Heat evolved = heat evolved in bond formation – heat required for bond breaking
`:. 90 kJ = [ H - Cl "bond energy"] - [1/2 xx 430 + 1/2 xx 240]`
`:. (H - Cl "bond energy") = 90 + (215 + 120) = 425 kJ mol^(-1)`.
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The H-H bond energy is 430KJ mol^(-1) and Cl-Cl bonds is 240KJ mol^(-1) . DeltaH for HCl is -90KJ . The H-Cl bond energy is about.

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Bond energies of H-H and Cl-Cl are "430 kJ mol"^(-1) and "242 kJ mol"^(-1) respectively. DeltaH_(f) for HCl is "91 kJ mol"^(-1) . What will be the bond energy of H-Cl ?

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From the following bond energies H-H bond energy 431.37 kJ mol^(-1) C=C bond energy 606.10 kJ mol^(-1) C-C bond energy 336.49 kJ mol^(-1) C-H bond energy 410.5 kJ mol^(-1) Enthalpy for the reaction overset(H)overset(|)underset(H)underset(|)(C )=overset(H)overset(|)underset(H)underset(|)(C )+H-HtoH-overset(H)overset(|)underset(H)underset(|)(C )-overset(H)overset(|)underset(H)underset(|)(C )-H will be