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The heat of atomisation of PH(3)(g) and ...

The heat of atomisation of `PH_(3)(g)` and `P_(2)H_(4)(g)` are `954 kJ mol^(-1)` and `1485 kJ mol^(-1)` respectively. The `P-P` bond energy in `kJ mol^(-1)` is

A

213

B

426

C

318

D

1272

Text Solution

Verified by Experts

The correct Answer is:
A
`3 (BE_(P-H) = 953`
`(BE_(P-H)) = 953//3`
`4 xx (BE_(P-H)) + (BE)_(P-P) = 1485`
`:. " "(BE_(P-H)) = 1485 - 4 xx 953/3 = 214.33 kJ//mol`.
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