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The enthalpy of neutraliztion of weak ba...

The enthalpy of neutraliztion of weak base A OH and a strong base BOH by HCl are -12250 cal/mol and -13000 cal/mol respectively . When one mole of HCl is added to a solution containting 1 mole of A OH and 1 mole of BOH , the enthalpy change was -12500 cal/mol . In what ratio is the acid distribution between A OH and BOH?

A

`2 : 1`

B

`2 :3`

C

`1 :2`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(1 mol)(AOH) + underset(x mol)(HCl) rarr ACl + H_2O , Delta H = -12250 cal = -12250 x cal`
`underset(1 mol)(BOH)+underset(x mol)(HCl) rarr BCl + H_2O , Delta H = -13000 cal = -13000 (1 - x) cal`
`12500 = 12250 x + 13000 (1 - x)`
`12500 = 12250 x + 13000(1 + x)`
`12500 = 12250 x + 13000 - 13000 x`
`x = 0.67`
`x/(1 - x) = (0.67)/(0.33) = 2 : 1`
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