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What is the bond enthalpy of Xe-F bond ?...

What is the bond enthalpy of `Xe-F` bond ?
`XeF_(4)(g)rarrXe^(+)(g)+F^(-)(g)+F_(2)(g)+F(g)," "Delta_(r)H=292"kcal/mol"`
Given : Ionization energy of `Xe=279"kcal/mol"`
`B.E.(F-F) = 38"kcal/mol"`, Electron affinity of F = 85 kcal/mol

A

`24 cal//mol`

B

`34 cal//mol`

C

`8.5 cal//mol`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`XeF_(4)(g) rarr Xe(g) + 4F(g)" "Delta_(a) H = ?`
`XeF_(4)(g) rarr Xe^(+)(g) + F^(-)(g) + F_(2)(g) + F(g) " "Delta_(r)H_(1) = 292 kcal//mol`
`Xe(g) rarr Xe^(+)(g) + e^(-) " "Delta_(x) H_(2) = 279 kcal//mol`
`F_(2)(g) rarr 2F(g) " "Delta_(r)H_(3) = 38 kcal//mol`
`F(g) + e^- rarr F^(-)(g) " "Delta_(r )H_(4) = -85 kcal//mol`
`implies "Required " Delta_(r )H = Delta_(r)H_1 + Delta_(r)H_3 -Delta_(r)H_4 = 292 - 279 + 38 -(-85) = 136 kcal//mol`.
`implies Delta_("mean, bond") Delta_(Xe-F) = 1/4 xx 136 = 34 kcal//mol`.
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