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The combustion of 0.2 mol of liquid carb...

The combustion of 0.2 mol of liquid carbon disulphide `CS_2` to give `CO_2(g) and SO_2(g)` releases 215 kJ of heat. What is `Delta H_(f)^(@) "for" CS_(2(l)) "in" kJmol^(-1)` :

A

772.1

B

87.9

C

-385

D

-475

Text Solution

Verified by Experts

The correct Answer is:
B
`CS_2 + 3O_(2) rarr CO_(2) + 2SO_(2)`
0.2 mole of `CS_2 = 215 kJ` of heat
1 mole of `CS_(2) = (215)/(0.2) = 1075 kJ` of heat
`Delta H_("comb") = 2 Delta H_(f)(SO_2) + Delta H_(f)(CO_2) - DeltaH_(f)(CS_2)`
`1075 = 2(-28=96.8) + (-393.5) - Delta H_(f)(CS_2)`
`1075 = 2(-296.8) + (-393.5) - Delta H_(f)(CS_2)`
`DeltaH_(f) (CS_2) = 2(-296.8) + (-393.5)-1075 = 87.9 kJ//mol`.
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