The heat of reaction for `N_(2)+3H_(2) rarr 2NH_(3)` at `27^(@)C` is `-91.94kJ` . What will be its value at `50^(@)C` ? The molar heat capacities at constant pressure and `27^(@)C` for `N_(2),H_(2)` and `NH_(3)` are `28.45, 28.32` and `37.07` joule respectively.

Options

A. `-92.843 kJ`
B. `-47.77723 kJ`
C. `-132.5 kJ`
D. `-176.114 kJ`

Answer

A

Explanation

Use `DeltaH_(2) - DeltaH_(1) = DeltaC_(p) [T_(2) - T_(1)]" "DeltaC_(p) = 2C_(pNH_(3)) -(C_(pN_2) + 3C_(PH_2))`