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AB,A(2) and B(2) are diatomic molecules....

`AB,A_(2)` and `B_(2)` are diatomic molecules. If the bond enthalpies of `A_(2), AB` and `B_(2)` are in the ratio `1:1:0.5` and the enthalpy of formation of `AB` from `A_(2)` and `B_(2)` is `-100kJ mol^(-1)` , what is the bond enthalpy of `A_(2)` ?

Text Solution

Verified by Experts

The correct Answer is:
400
`in_(A - A) = x " " in_(A - B) = x " "in_(B - B) = x//2`
`1/2 A_(2) + 1/2 B_(2) rarr AB`
`1/2 x + x/4 - x = -100 implies x = 400`
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