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If, H(2)(g)+Cl(2)(g)rarr 2HCl(g) , Delta...

If, `H_(2)(g)+Cl_(2)(g)rarr 2HCl(g) , Delta H^(@)=-44` Kcal
`2Na(s)+2HCl(g)rarr 2NaCl(s)+H_(2)(g), Delta H=-152` Kcal Then, `Na(s)+0.5Cl_(2)(g)rarr NaCl(s) , Delta H^(@) = ?`

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The correct Answer is:
196
By equation (i) + (ii)
`2Na + Cl_(2) rarr 2NaCl , Delta H = -196 kcal`
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