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Heat of combustion DeltaH^(@) for C(s),H...

Heat of combustion `DeltaH^(@)` for `C(s),H_(2)(g)` and `CH_(4)(g)` are `94, -68` and `-213Kcal//mol` . Then `DeltaH^(@)` for `C(s)+2H_(2)(g)rarrDeltaCH_(4)(g)` is

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The correct Answer is:
17
`Delta H = (DeltaH_("comb")CH_4) - [DeltaH_("comb")C(s) + 2 xx Delta H_("comb")H_(2)(g)] = 17 cal` .
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