Enthalpy of combustion of carbon to `CO_(2)` is `-393.5 kJ mol^(-1)`. Calculate the heat released upon formation of `35.2 g` of `CO_(2)` from carbon and dioxygen gas.

Answer

314.8

Explanation

`C(s) + O_(2)(g) rarr CO_(2)(g) , " "Delta H = -393.5 kJ mol^(-1)`
`44g CO_(2)` is formed then heat released is `=393.5 kJ mol^(-1)`
`35.2 g CO_(2)` is formed then heat released =`(393.5 xx 35.2)/(44) kJ = 314.8 kJ`