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The combustion of benzene (l) gives CO(2...

The combustion of benzene (l) gives `CO_(2)(g)` and `H_(2)O(l)`. Given that heat of combustion of benzene at constant volume is `–3263.9 kJ mol^(–1)` at `25^(@)C`, heat of combustion (in kJ` mol^(–1)`) of benzene at constant pressure will be
(R = 8.314 JK–1 mol–1)

A

3260

B

`-3 2 6 7 . 6`

C

`4152.6`

D

`-4 5 2 . 4 6`

Text Solution

Verified by Experts

The correct Answer is:
B
`C_(6)H_(6)(l) + 15/2 O_(2)(g) rarr 6CO_(2)(g) + 3H_(2)O(l)`
`Delta _(g) = -3/2`
`Delta H = Delta U + Deltan_((g)) RT = -3263.9 -(1.5 xx 8.314 xx 298)/(1000) = -3267.6 kJ//mol`.
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