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Compute the heat of formation of liquie ...

Compute the heat of formation of liquie methyl alcohol is kilojoule per mol using the following data. Heat of vaporisation of liquid methyl alcohol `=38kJ//mol`. Heat of formation of gaseous atoms from the elements in their standard states `:H=218kJ // mol, C=715kJ //mol, O=249kJ //mol.`
Average bond energies`:`
`C-H415kJ//mol, C-O 356kJ//mol, O-H 463kJ //mol.`

Text Solution

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Given `CH_(3) OH(g) to CH_(3)OH(l) , Delta H = -38 kJ`
`C(g) + 4H(g) rarr CH_(3)OH(g) , DeltaH = -(3 xx 415 + 356 + 463)`
`:. H = H_(1) + H_(2) = - 2064 kJ`
`C(s) to C(g) , Delta H = 715 kJ`
`2H_(2)(g) rarr 4H(g) , Delta H = 2 xx 2 xx 218 = 872 kJ`
Adding : `(1/2O_(2)(g) to O(g) , Delta H = 249 kJ)/(C(gr) + 2H_(2)(g) + 1/2 O_(2) (g) to CH_(3)OH(l))`
`Delta H = -265 kJ//mol`.
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