`100mL` of a liquid is contained in an insulated container at a pressure of 1bar. The pressure is steeply increased to `100`bar. The volume of the liquid is decreased by `1mL` at this constant pressure. Find `DeltaH` and `DeltaU`.

Options

A. 200 bar mL, 8000 bar mL
B. 300 bar mL, 7000 bar mL
C. 100 bar mL, 9900 bar mL
D. 350 bar mL, 870 bar mL

Explanation

Volume of 1 mole liquid = 100 mL, at pressure 1 bar
Volume of 1 mole liquid = 99 mL at pressure 100 bar
The process being irreversible as it is steeply changed from 1 bar to 100 bar
`w=-P(V_(2)-V_(1)) = -100 xx (99 -100) = 100 bar mL`
Also, `DeltaE = q+w`
`DeltaE = w` `(therefore q=0, "adiabatic nature due to insulation")`
`DeltaE = 100` bar mL
Also, `DeltaH = DeltaE + PDeltaV = DeltaE + (P_(2)V_(2) - P_(1)V_(1))`
`=100 + (100 xx 99-1 xx 100) = 9900` bar mL