The reaction `A to B` , `DeltaH=+24 kJ//"mole"`. For the reaction `B to C`, `DeltaH=-18 kJ//"mole"`. The decreasing order of enthalpy of `A`, `B`, `C` follow the order

Options

A. A,B,C
B. B,C,A
C. C,B,A
D. C,A,B

Answer

B

Explanation

`A to B, DeltaH = +24 (kJ)/mol`
`rArr H_(B)-H_(A) = +24`…………(i)
`B to C, DeltaH = -18 kJ//mol`
`rArr H_(C) - H_(B) = -18`………(ii)
`rArr H_(B) - H_(C) = +10`
From equations (i) and (ii), we have
`H_(C) - H_(A) = 6`
`H_(B) gt H_(C) gt H_(A)`