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Calculate the free energy change at 298 ...

Calculate the free energy change at 298 K for the reaction,
`Br_(2)(l)+ Cl_(2)(g) rarr 2BrCl(g)`. For the reaction `DeltaH^(@)=29.3` KJ & the entropies of `Br_(2)(l),Cl_(2)(g)` & `BrCl(g)` at the 298 K are 152.3,223.0,239.7 J `"mol^(-1)K^(-1)` respectively.

A

`-1721.8` J

B

`-60321.8` J

C

`+60321.8` J

D

`+1721.8` J

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG = 29.3 xx 10^(3) - (2 xx 239.7-152.3 - 223) xx 298 =-1721.8` Joule
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