Home
Class 12
CHEMISTRY
For the reaction at 298 K A(g) + B(g) ...

For the reaction at `298 `K
`A(g) + B(g) hArr C(g) + D(g)`
If `DeltaH^(@) =-29.8` Kcal and `DeltaS^(@) Kcal K^(-1)` then calculate reaction constant (k)

A

1

B

0

C

2

D

4

Text Solution

Verified by Experts

The correct Answer is:
B
`therefore G^(@) = DeltaH^(@) - T. DeltaS^(@) -29.8 -2.98 xx (-0.1) = -29.8 + 29.8 =0`
Promotional Banner

Similar Questions

Explore conceptually related problems

For the reaction at 298 K A(g) + B(g) iff C(g)+ D(g) DeltaH^(@) = -29.8 Kcal, DeltaS^(@) = - 0.1 Kcal //K Calculate DeltaG^(@) and K.

For the reaction at 298 K : A_((g))+B_((g))hArrD_((g))+C_((g)) DeltaH^(@)=29.8 kcal and DeltaS^(@)=100calK^(-1) . Calculate the value of equilibrium constant.

For the reaction at 298 k, A(g) +B(g) hArr C(g) +D(g) DeltaH_0=-29.8 kcal, DeltaS^@=-0.100 kcal K^(-1) Find the value of equilibrium constant at the same temp.

For the reaction, 2A (s) + 2B (g)to C (g) + D(s) at 298K Delta U ^(@) =-10.5KJ and Delta S ^(@)=-44.10 JK^(-1) Calculate Delta G ^(@) for the reaction (in Joules).

Find the value of DeltaG^(@) if the DeltaH^(@)=-29.8 kcal and DeltaS^(@)=-0.100 kcal K^(-1) is given at 298K.

The K_c for given reaction will be A_2 (g) +2B (g) hArr C(g) +2D(s)

For the reaction at 300 K A(g)+B(g)toC(g)" Delta"E=-3.0"kcal",DeltaS=-10.0cal//K value of DeltaG is