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For a particular reversible reaciton at ...

For a particular reversible reaciton at temperature `T, DeltaH` and `DeltaS` were found to be both `+ve`. If `T_e` is the temperature at equilibrium, the reaciton would be spontaneous when :

A

`T_(e) gt T`

B

`T gt T_(e)`

C

`T_(e)` is 5 times T

D

`T = T_(e)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG = DeltaH - TDeltaS` at equilibrium, `DeltaG =0`
For a reaction to be spontaneous `DeltaG` should be negative, so T should be greater than `T_(e)`.
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