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A schematic plot of ln K(eq) versus inve...

A schematic plot of ln `K_(eq)` versus inverse of temperature for a reaction is shown below: The reaction must be:

A

Highly spontaneous at ordinary temperature

B

One with negligible enthalpy change

C

endothermic

D

exothermic

Text Solution

Verified by Experts

The correct Answer is:
D
Variation of `K_(eq)` with temperature t is given by van't Hoff equation ln `K_(eq) = -(DeltaH^(@))/(R/A) .1/T + (DeltaS^(@))/(R/R)`
Slope of the given line is positive indicating that term A is positive, thus `DeltaH^(@)` is negative. Thus, reaction is exothermic.
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