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Standard entropy of X(2) , Y(2) and XY(3...

Standard entropy of `X_(2)` , `Y_(2)` and `XY_(3)` are `60, 40 ` and `50JK^(-1)mol^(-1)` , respectively. For the reaction, `(1)/(2)X_(2)+(3)/(2)Y_(2)rarrXY_(3),DeltaH=-30KJ` , to be at equilibrium, the temperature will be:

A

1000 K

B

1250 K

C

500 K

D

750 K

Text Solution

Verified by Experts

The correct Answer is:
D
`1/2 X_(2) + 3/2Y_(2) , XY_(3)`
`DeltaS = 50 -(1/2 xx 60 + 3/2 xx 40) = 50-90 = -40 kJ//mol`
`DeltaG = 0=-30 xx10^(3) - T xx (-40)`
`40 T = 30 xx 10^(3) rArr T = 750 K`
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