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A reaction has DeltaH=-33kJ and DeltaS=-...

A reaction has `DeltaH=-33kJ and DeltaS=-58J//K`. This reaction would be:

A

Spontaneous at all temperature

B

non-spontaneous at all temperatures

C

spontaneous above a certain temperature only

D

spontaneous below a certain temperature only

Text Solution

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The correct Answer is:
D
`DeltaS = -ve`
`DeltaH = -ve`
`DeltaG = DeltaG = DeltaH - TDeltaS`
For a reaction to be spontaneous, `DeltaG = -ve` which can be below a certain temperature only
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