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One gram sample of oxygen undergoes free...

One gram sample of oxygen undergoes free expansion from 0.75L to 3.0 L at 298 K. Calculate `DeltaS`, q,w `DeltaH "and" DeltaE`

A

`DeltaS-=0.36 JK^(-1)`

B

`W = 227.97` J

C

`q=-227.97`J

D

`DeltaH=107.28` J

Text Solution

Verified by Experts

The correct Answer is:
A
Since, expansions occurred at constant temperature.
`DeltaS = nR ln V_(2)/V_(1) = 1/32 xx 8.314 ln 3.0/(0.75) = 0.36 JK^(-1)`
Since, this in case of free expansion, `P_(ext)=0 rArr -W = P_(ext)DeltaV = 0, q=0`
Alos, since, `DeltaT = 0 rArr DeltaH = DeltaE =0`.
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