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One moles of an ideal gas which C(V) = 3...

One moles of an ideal gas which `C_(V) = 3//2 R` is heated at a constant pressure of `1 atm` from `25^(@)C` to `100^(@)C`. Calculate `DeltaU, DeltaH` and the entropy change during the process.

Text Solution

Verified by Experts

The correct Answer is:
`223.53`
`C_(p) = C_(v) + R = (3//2) R + R=5/2 R`
At constant pressure
Heat given to 1 mole gas `=C_(p)DeltaT`
Or `DeltaH = q_(p) =1 xx (5//2) R xx (373-298)`
Or `DeltaH = q_(p) = 1 xx (5//2) xx 1.987 xx 75`
`DeltaH = q_(p) = 372.56` cal
Also, work done in process (irreversible)
`DeltaU = q+w = 372.56 - 149.03 = 223.53` cal
`-nR (T_(2)-T_(1))=-1 xx 1.987 xx (373 -298) = -149.03` cal
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