Home
Class 12
CHEMISTRY
Calculate the change in entropy for the ...

Calculate the change in entropy for the fusion of 1 mole of ice (water). The melting point of water is 273 K and molar enthalpy of funsion for water `=6.0 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
2.98

Entrop change of fusion, `DeltaS_(t) = DeltaH_(f)//T`
`DeltaH_(f) = 6 xx 10^(3) J, T =273 K`
`DeltaS_(f) = (6 xx 10^(3))/273 = 21.98 JK^(-1) mol^(-1)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the change in entropy for the fusion of 1 mol of ice. The melting point of ice is 273 K and molar enthalpy of fusion of ice = 6KJmol^(-1)

Calculate the change in entropy for the fusion of 1 mol of ice. The melting point of ice is 300K and molar enthalpy of fustion for ice = 6.0 k J mol^(-1) .

(i) Calculate the change in entropy for the fusion of 1 mole of ice. The melting point of ice is 273 K and molar enthalpy of fusion for ice = 6.0 kJ/mole. (ii) Calculate the standard of entropy change for the following reaction. {:(,H^(+)(aq), + OH(aq)to, H_(2)O(l)),(S^(@)(298 K)//JK^(-1)mol^(-1),0,-10.7,+70):}

Calculatte the molal elevation constant of water if molar enthalpy of vapourisation of water at 373K is 40.585 kJ mol^(-1) .

The entropy of fusion of water is 5.260 cal//"mole" K calculate the enthalpy of fusion of water ?

When ice melts into water, entropy

What is entropy change for the conversion of one gram of ice to water at 273 K and one atmospheric pressure? (DeltaH_("fusion")=6.025kJ" "mol^(-1))