one mole of an ideal gas at 300k in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant presses of 3.0 atm. In this process. The change in entropy of surrroundings `(DeltaS)` in `J^(-1)` is
(1 L atm = 101.3 J)

Explanation

`DeltaS_("suit") = (q_("suit"))/T = -(q_("says"))/T = (W_("says))/T`
`DeltaS_("suit") = (-P_(ext) (V_(f)-V_(i))/T) = -3((2-1)/300) L atm K^(-1)`
`=-0.01 L atm K^(-1) = -0.01 xx 101.3 JK^(-1) = -1.013 JK^(-1)`