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For silver, Cp(JK^(-1)mol^(-1))=23+0.01T...

For silver, `C_p(JK^(-1)mol^(-1))=23+0.01T` If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of 'Delta H' will be close to

A

21 kJ

B

13 kJ

C

16 kJ

D

62 kJ

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaH = int nC_(p)dT = 3 int_(300)^(1000) (2.3 + 0.01 T) dT - 3[23T + (0.01T^(2))/2]_(30.0)^(1000)`
`=3[23000 + 0.01/2 (1000)^(2)-23(300)-(0.01(300)^(2))/2]`
`=3[23000 + 5000 - 6900 - 450] = 61950` J = 62 kJ
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