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A ("(l)") to 2 B ( "(g)") ...

` A _ ("(l)") to 2 B _ ( "(g)") `
` Delta U = 2. 1 ` kcal ,` Delta S = 20 ` Cal/k, T = 300 K.
Find ` Delta G ` ( in kcal )

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The correct Answer is:
`-2.70`
`A(l) to 2B(g)`
`DeltaU = 2.1 kcal, DeltaS = 20 cal//k, T=300 K`
`DeltaG = DeltaH - T DeltaS`
`DeltaH = DeltaH + Delta ngRT , Delta ng=2`
`DeltaG = 3300 - (300)(20) = 3300 - 6000 = -2700 cal = -2.7` kcal
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