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One mole of non-ideal gas undergoes a ch...

One mole of non-ideal gas undergoes a change of state (`2.0 "atm"`, `3.0 L`, `95 K`) `to` (`4.0 "atm"`, `5.0 L`, `245 K`) with a change in internal energy, `DeltaU=30.0 L atm`. The change in enthalpy `(DeltaH)` of the process in `L "atm"` is

A

40

B

42.3

C

44

D

not defined, because pressure is not constant

Text Solution

Verified by Experts

The correct Answer is:
c
`DeltaH = DeltaU + Delta(pv), DeltaH = DeltaU + (p_(2)V_(2)-p_(1)v_(1))`
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