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When 1mol of a monoatomic ideal gas at T...

When `1mol` of a monoatomic ideal gas at `TK` undergoes adiabatic change under a constant external pressure of `1atm`, changes volume from `1 L to 2L`. The final temperature (in K) would be

A

`T/(2^(2//3))`

B

`T+ 2/(3 xx 0.0821)`

C

T

D

`-2/(3 xx 0.0821)`

Text Solution

Verified by Experts

The correct Answer is:
d
For an irreversible, adiabatic process, `0=C_(v)(T_(2)-T_(1)) + P_(e)(V_(2)-V_(1))`
Substituting the values `C_(v) (T-T_(2)) = 1(2-1)` atm L
`rArr T-T_(2) = 1/C_(v) =1/(Cv) -2/(3R) rArr T_(2) = T-2/(3 xx 0.082)`
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