Home
Class 12
CHEMISTRY
N(2)+3H(2)hArr2NH(3) Which is correct ...

`N_(2)+3H_(2)hArr2NH_(3)`
Which is correct statement if `N_(2)` is added at equilibrium condition?

A

The equilibrium will shift to forward direction because according to Iind law of the thermodynamcis the entropy must increase in the direction of spontaneous reaction.

B

The condition for equilibrium is `G_(N_(2)) + 3G_(NH_(3)) = 2G_(NH_(3))`, where G is Gibbs free energy per mole of the gaseous species measured at that partial pressure. The condition of equilibrium is unaffected by the ue of catalyst, which increases the rate of both the forward and backward reactions to the same extant.

C

The catalyst will increase the rate of forward reaction by `alpha` and that of backward reaction by `beta`.

D

Catalyst will not alter the rate of either of the reaction.

Text Solution

Verified by Experts

The correct Answer is:
b

Catalyst does not after the equilibrium established in lesser time in the presence of catalyst.
Promotional Banner

Similar Questions

Explore conceptually related problems

N_(2)+3H_(2) hArr 2NH_(3) Which of the following statements is correct if N_(2) added at equilibrium condition?

For the reaction, N_(2)+3H_(2)hArr2NH_(3) , in a vessel equal moles of N_(2) and H_(2) are mixed to attain equilibrium. At equilibrium:

N_(2)(g) and H_(2)(g) are allowed to react in a closed vessel at given temp. and pressure for the formation of NH_(3)(g),[N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)+22.4kcal] If he (g) is added at equilibrium at constant pressure than which is/are correct ?

For the synthesis of ammonia by the reaction N_(2)+3H_(2)hArr2NH_(3) in the Haber's process ,the attainment of equilibrium is correctly predicated bt the curve

For N_(2)+3H_(2)hArr 2NH_(3) , 1 mole N_(2) and 3 mol H_(2) are at 4 atm. Equilibrium pressure is found to be 3 atm. Hence, K_(p) is