A reversible cyclic process for an ideal gas is shown below. Here, P, V, and T are pressure, volume and temperature, respectively. The thermodynamic parameters q, w, H and U are heat, work, enthalpy and internal energy, respectively.

The correct option (s) is (are)

Options

A. `q_(AC) = DeltaU_(BC)`
B. `W_(BC) = P_(2)(V_(2)-V_(1))` and `q_(BC) = DeltaH_(AC)`
C. `DeltaH_(CA) lt DeltaU_(CA)` and `q_(AC) = DeltaU_(BC)`
D. `q_(BC) = DeltaU_(AC)` and `DeltaH_(CA) gt DeltaU_(CA)`

Answer

bc

Explanation

`q_(AC) = DeltaU_(AC) =nC_(V) [T_(2)-T_(1)] = Delta U_(BC)`
`W_(AB) = -nRT_(1) ln V_(2)/V_(1)`
`W_(BC) = -P_(2)[V_(1)-V_(2)] = P_(2)[V_(2)-V_(1)]`
`q_(BC) =Delta_(BC) = nC_(p)[T_(2)-T_(1)] = DeltaH_(AC)`
`DeltaH_(CA) = nC_(p) [T_(1)-T_(2)]`
`DeltaU_(CA) = nC_(V) [T_(1)-T_(2)]`
`DeltaH_(CA) lt DeltaU_(CA)` because both are negative and `T_(1) lt T_(2)`