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Three moles of PCl(5), three moles of PC...

Three moles of `PCl_(5)`, three moles of `PCl_(3)` and two moles of `Cl_(2)` are taken in a closed vessel. If at equilibium, the vessel has 1.5 moles of `PCl_(5)` the number of moles of `PCl_(3)` present in it is

A

5

B

3

C

6

D

4.5

Text Solution

Verified by Experts

The correct Answer is:
D
`PCl_(5) rarr PCl_(3)+Cl_(2)`
Hence `n_(PCl_(3)) = 4.5`
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