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In chemical equilibrium, the value of De...

In chemical equilibrium, the value of `Delta n` (number of molecules), is negative, then the relationship between `K_(p) "and" K_(c)` will be

A

`K_(P)-K_(c) = 0`

B

`K_(c) = K_(P) xx (RT)^(+Deltan)`

C

`K_(P) = K_(c) xx (RT)^(-Deltan)`

D

`K_(c) = 1/K_(p)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Kp = Kc(RT)^(Deltang)`
Since, `Delta(ng)` is -ve
`Kc = Kp(RT)^(+Deltang)`
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