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Consider the following reaction equilibr...

Consider the following reaction equilibrium
`N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g)`
Initially, 1 mole of `N_(2)` and 3 moles of `H_(2)` are taken in a 2 L flask. At equilibrium state if, the number of moles of `N_(2)` is 0.6, what is the total number of moles of all gases present in the flask ?

A

0.8

B

1.6

C

3.2

D

6.4

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g)`
`1-x = 0.6 implies x = 0.4`
Total moles = 4 - 2x = 3.2
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