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For PCl(5)hArr PCl(3)+Cl(2), initial con...

For `PCl_(5)hArr PCl_(3)+Cl_(2)`, initial concentration of each reactant and product is 1 M. If `K_(eq)=0.41` then

A

More `PCl_(3)` will form

B

More `Cl_(2)` will form

C

More `PCl_(5)` will form

D

No change

Text Solution

Verified by Experts

The correct Answer is:
C
Since value of `K_(c)` is less than 1 it means concentration of product at equilibrium is less than concentration of reactant. Hence more `PCl_(5)` will form.
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