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Phosphorus pentachloride dissociates as ...

Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, `PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g))` If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of `PC1_(5)` is x, the partial pressure of `PC1_(3)` will be:

A

`(x/(x+1))p`

B

`(2x/(1+x))p`

C

`(x/(x-1))p`

D

`(x/(1-x))p`

Text Solution

Verified by Experts

The correct Answer is:
A
`PCl_(5) rarr PCl_(3) + Cl_(2)`
`n_(total) = C + Cx`
Mole fraction of `PCl_(3)`
`X_(PCl_(3)) = Cx/(C+Cx)`
Partial pressure of `PCl_(3) = X_(PCl_(3))`.Total pressure
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