Home
Class 12
CHEMISTRY
What is the value of k(c) for the reacti...

What is the value of `k_(c)` for the reaction at 1473 K
`I_(2)(g) hArr 2I(g)`
when one mode of iodic gas is introduced into an evacuated one litre flask so that only 5% of it gets dissociated ?

A

0.0105

B

0.046

C

0.034

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
A

For this reaction `I_(2)(g) rarr 2I(g)`
`K_(c) = [I]^(2)/[I_(2)] = (2x)^(2)/(1-x)`
As degree of dissociation of 5%
x = 0.05
`K_(c) = (2 xx 0.05)^(2)/(1-0.05) = 0.01/0.95 = 0.0105`
Promotional Banner

Similar Questions

Explore conceptually related problems

K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The relation K_(p) " and " K_(c) for the reaction: 2NO (g) + CI_(2) (g) hArr 2NOCI(g) " is":

For the reaction I_(2)(g) hArr 2I(g) , K_(c) 37.6 xx 10^(-6) at 1000K . If 1.0 mole of I_(2) is introduced into a 1.0 litre flask at 1000K, at equilibrium

For reaction H_(2)(g) +I_(2)(g) hArr 2HI (g) The value of K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) The equilibrium constant K_(p) changes with