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Two solid compounds X and Y dissociates ...

Two solid compounds X and Y dissociates at a certain temperature as follows
`X(s) hArr A(g)+2B(g),K_(p1)=9xx10^(-3)atm^(3)`
`Y(s) hArr 2B(g)+C(g),K_(p2)=4.5xx10^(-3)atm^(3)`
The total pressure of gases over a mixture of X and Y is `:`

Text Solution

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`A(g) rarr X(g) + 2Y(g)`
`B(s) rarr X(g) + 2Y(g)`
`B(s) rarr Z(g) + 2Y(g)`
Thus,`K_(P_(1))/K_(P_(2)) = P_(1) xx (2P_(1) + 2P_(2))/P_(2) xx (2P_(1) + 2P_(2)) = P_(1)/P_(2) = 9 xx 10^(-2)/4.5 xx 10^(-3) = 2`
`P_(1) = 2P_(2)`
Also, `K_(P_(1)) = 9 xx 10^(-3) = P_(1) xx (2P_(1) + 2P_(2))^(2) = P_(1) xx (2P_(1) + P_(1))^(2) = 9P_(1)^(3)`
`P_(1) = 0.1 atm, P_(2) = 0.05 atm ,`
`P_(T) = 2P_(1) + 2P_(2) + P_(1) + P_(2) = 3(P_(1)+P_(2)) = 3 xx 0.15 = 0.45 atm`
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