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How many mole of glycerine should be add...

How many mole of glycerine should be added to 1 litre of 1 M `H_(3)BO_(3)` so that 80% of boric acid form boric acid-glycerine complex ?
`H_(3)BO_(3) +` Glycerine `rarr `Complex` Kc = 0.90`

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To solve the problem, we need to determine how many moles of glycerine should be added to 1 liter of 1 M \( H_3BO_3 \) (boric acid) so that 80% of the boric acid forms a complex with glycerine. ### Step-by-Step Solution: 1. **Determine Initial Moles of Boric Acid:** - Given that the concentration of \( H_3BO_3 \) is 1 M and the volume is 1 L, the initial moles of boric acid are: \[ \text{Initial moles of } H_3BO_3 = 1 \, \text{M} \times 1 \, \text{L} = 1 \, \text{mole} ...
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The equilibrium constant for the following reaction in aqueous solution is 0.90. H_(3)BO_(3)+"glycerin"hArr(H_(3)BO_(3)-"glycerin") How many mole of glycerin should be added per litre of 0.10 M H_(3)BO_(3) so that 80% of the H_(3)BO_(3) is converted to the boric-acid glycerin complex ?

Boric acid H_(3)BO_(3) is a:

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The total number of protons donated by one molecule of (H_(3)BO_(3)) boric acid is

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Basicity of boric acid + Basicity of H_(3)PO_(2)+ Basicity of H_(3)PO_(3) is: