Home
Class 12
CHEMISTRY
A definite amount of solid NH(4)HS is pl...

A definite amount of solid `NH_(4)HS` is placed in a flask aleady containing ammoina gas at a certain temperature and `0.50` atm pressure. `NH_(4)HS` decomposes to give `NH_(3)` and `H_(2)S` and at equilibrium total pressure in flask is `0.84` atm. The equilibrium constant for the reaction is:

Text Solution

Verified by Experts

`NH_(4)HS(g) rarr NH_(2)(g) + H_(2)(g)`
`P_(T) = 0.84 = 0.5 +P+P`
`K_(P) = P'_(NH_(3)) xx P_(H_(2)S) = (0.5 + 0.17) xx 0.17 = 0.11 atm^(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A definite amount of solid NH_(4)HS is placed in a flask already containing ammonia gas at a certain temperature and 0.1 atm pressure. NH_(4)HS decompses to give NH_(3) and H_(2)S and at equilibrium total pressure in flask is 1.1 atm. If the equilibrium constant K_(P) for the reaction NH_(4)HS(s) iff NH_(3)(g)+H_(2)S(g) is represented as zxx10^(-1) then find the value of z.

An amount of solid NH_4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure.Ammonium hydrogen sulphide decomposes to yield NH_3 and H_2S gases in the flask.When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm ? The equilibrium constant for NH_4HS decomposition at this temperature is :