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Pure ammonia is placed in a vessel at a ...

Pure ammonia is placed in a vessel at a temperature where its dissociation constant (`alpha`) is appreciable. At equilibrium, `N_(2) + 3H_(2) rarr 2NH_(3)`

A

`K_(p)` does not change significantly with pressure

B

`alpha` does not change with pressure

C

concentration of `NH_(3)` does not change with pressure

D

concentration of hydrogen is less than that of nitrogen

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To solve the problem regarding the dissociation of ammonia at equilibrium, we need to analyze the given reaction and the implications of the dissociation constant (α) being appreciable. ### Step-by-Step Solution: 1. **Understanding the Reaction**: The reaction given is: \[ N_2 + 3H_2 \rightleftharpoons 2NH_3 \] This indicates that nitrogen and hydrogen gases combine to form ammonia. 2. **Equilibrium Constant Expression**: The equilibrium constant \( K_p \) for the reaction can be expressed as: \[ K_p = \frac{(P_{NH_3})^2}{(P_{N_2})(P_{H_2})^3} \] where \( P_{NH_3} \), \( P_{N_2} \), and \( P_{H_2} \) are the partial pressures of ammonia, nitrogen, and hydrogen, respectively. 3. **Effect of Temperature**: It is stated that the dissociation constant \( \alpha \) is appreciable, which implies that the equilibrium position is significantly shifted towards the reactants (N2 and H2). However, \( K_p \) is only affected by temperature and not by changes in pressure or concentration. 4. **Pressure and Kp**: According to Le Chatelier's principle, while changes in pressure can affect the position of equilibrium, the value of \( K_p \) itself remains constant at a given temperature. Therefore, the statement that \( K_p \) does not change significantly with pressure is true. 5. **Conclusion**: Since the question asks about the behavior of \( K_p \) and its dependence on temperature, we conclude that the correct option is that \( K_p \) does not change significantly with pressure. ### Final Answer: The correct statement regarding the dissociation of ammonia at equilibrium is that \( K_p \) does not change significantly with pressure; it depends only on temperature. ---

To solve the problem regarding the dissociation of ammonia at equilibrium, we need to analyze the given reaction and the implications of the dissociation constant (α) being appreciable. ### Step-by-Step Solution: 1. **Understanding the Reaction**: The reaction given is: \[ N_2 + 3H_2 \rightleftharpoons 2NH_3 ...
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