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In which one of the following equilibria...

In which one of the following equilibria, `K_(p) = K_(c)` ?

A

`2NO(g) rarr N_(2)(g) + O_(2)(g)`

B

`2C(s) + O_(2)(g) rarr 2CO(g)`

C

`2HI(g) rarr H_(2)(g) + I_(2)(g)`

D

`NO_(2)(g) + SO_(2)(g) rarr NO(g) + SO_(2)(g)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which equilibrium \( K_p = K_c \), we need to analyze the given reactions based on the relationship between \( K_p \) and \( K_c \). The relationship is given by the equation: \[ K_p = K_c (RT)^{\Delta n} \] where: - \( R \) is the ideal gas constant, - \( T \) is the temperature in Kelvin, - \( \Delta n \) is the change in the number of moles of gas, calculated as \( \Delta n = n_p - n_r \) (moles of products minus moles of reactants). ### Step-by-Step Solution: 1. **Identify the Reactions**: We need to analyze the provided reactions to find \( \Delta n \) for each. 2. **Calculate \( \Delta n \)**: - For each reaction, count the number of moles of gaseous products and reactants. - Use the formula \( \Delta n = n_p - n_r \). 3. **Determine \( K_p \) and \( K_c \)**: - If \( \Delta n = 0 \), then \( K_p = K_c \) because \( (RT)^{\Delta n} = (RT)^0 = 1 \). - If \( \Delta n \neq 0 \), then \( K_p \) will not equal \( K_c \). 4. **Analyze Each Option**: - For each reaction option provided, calculate \( \Delta n \) and check if it equals zero. 5. **Conclusion**: - The reaction for which \( \Delta n = 0 \) is the one where \( K_p = K_c \). ### Example Calculation: Assuming we have the following reactions: 1. \( N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \) - \( n_p = 2 \) (from \( 2NO \)) - \( n_r = 2 \) (from \( N_2 + O_2 \)) - \( \Delta n = 2 - 2 = 0 \) → \( K_p = K_c \) 2. \( 2C(s) + O_2(g) \rightleftharpoons 2CO(g) \) - \( n_p = 2 \) (from \( 2CO \)) - \( n_r = 1 \) (from \( O_2 \)) - \( \Delta n = 2 - 1 = 1 \) → \( K_p \neq K_c \) 3. \( H_2(g) + I_2(g) \rightleftharpoons 2HI(g) \) - \( n_p = 2 \) (from \( 2HI \)) - \( n_r = 2 \) (from \( H_2 + I_2 \)) - \( \Delta n = 2 - 2 = 0 \) → \( K_p = K_c \) ### Final Answer: The equilibria for which \( K_p = K_c \) are those where \( \Delta n = 0 \).

To determine in which equilibrium \( K_p = K_c \), we need to analyze the given reactions based on the relationship between \( K_p \) and \( K_c \). The relationship is given by the equation: \[ K_p = K_c (RT)^{\Delta n} \] where: - \( R \) is the ideal gas constant, ...
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