Home
Class 12
CHEMISTRY
If equilibrium constant for the reaction...

If equilibrium constant for the reaction
`A_(2)+B_(2) hArr 2AB` is k, then for the backward reaction `AB hArr 1//2 A_(2)+1//2B_(2)` the equilibrium constant k' is `1//K`.

Text Solution

Verified by Experts

`R xx n` is reversed and multiplied by 1/2 . So `K_(new)^(eq) = sqrt(1/K)`
Promotional Banner

Similar Questions

Explore conceptually related problems

If the equilibrium constant for the reaction A_(2)+B_(2) hArr 2AB is K, then the backward reaction, AB hArr 1/2 A_(2)+1/2 B_(2) the equilibrium constant is 1//K .

The equilibrium constant for a reaction A+2B hArr 2C is 40 . The equilibrium constant for reaction C hArr B+1//2 A is

If K for the reaction : 2AB hArr A_2+B_2 is 50, then K' for the reaction A_2+B_2 hArr 2AB is ______

The equilibrium constant for the reversible reaction N_(2)+3H_(2) hArr 2NH_(3) is K and for the reaction (1)/(2) N_(2)+(3)/(2) H_(2) hArr NH_(3) , the equilibrium constant is K',.K and K' will be related as

The unit of equilibrium constant K_(c) for the reaction A+B hArr C would be

If equilibrium constant for reaction 2AB = A_(2) + B_(2) . Is 49, then the equilibrium constant for reaction AB ltimplies 1/2_(A_(2)) + 1/2_(B_(2)) , will be:

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant for the reactions A+B hArr AB is 0.5 at 200K . The equilibrium constant for the reaction AB hArr A+B would be

The equilibrium constant for the reaction A_(2)(g)+B_(2)(g) hArr 2AB(g) is 20 at 500K . The equilibrium constant for the reaction 2AB(g) hArr A_(2)(g)+B_(2)(g) would be